What are the solutions to the equation completesquare x^2+4x+7=0 ?

The solutions to the equation completesquare x^2+4x+7=0 are x=sqrt(3)i-2,x=-sqrt(3)i-2

Find the zeros of completesquare x^2+4x+7=0

The zeros of completesquare x^2+4x+7=0 are x=sqrt(3)i-2,x=-sqrt(3)i-2

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x^{2} + 4 x + 7 = 0

x = 3 i - 2, x = - 3 i - 2

Solution steps

x^{2} + 4 x + 7 = 0

Move

7

to the right side

x^{2} + 4 x = - 7

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = - 3

For

the solutions are

f (x) = a, - a

Solve

x + 2 = - 3 : x = 3 i - 2

Solve

x + 2 = - - 3 : x = - 3 i - 2

The solutions to the quadratic equation are:

x = 3 i - 2, x = - 3 i - 2

3 x^{2} - 12 x - 11

A = x^{2} + 12 x + 27

x^{2} - 6 x + 15 = 10

0.02 x^{2} - 0.3 x = 20

4 x^{2} + 10 x - 4 = 0

What are the solutions to the equation completesquare x^2+4x+7=0 ?
The solutions to the equation completesquare x^2+4x+7=0 are x=sqrt(3)i-2,x=-sqrt(3)i-2
Find the zeros of completesquare x^2+4x+7=0
The zeros of completesquare x^2+4x+7=0 are x=sqrt(3)i-2,x=-sqrt(3)i-2