What are the solutions to the equation 0.01y^2-0.02y-0.01=0 ?

The solutions to the equation 0.01y^2-0.02y-0.01=0 are y=1+sqrt(2),y=1-sqrt(2)

Find the zeros of 0.01y^2-0.02y-0.01=0

The zeros of 0.01y^2-0.02y-0.01=0 are y=1+sqrt(2),y=1-sqrt(2)

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0.01 y^{2} - 0.02 y - 0.01 = 0

y = 1 + 2, y = 1 - 2

Solution steps

0.01 y^{2} - 0.02 y - 0.01 = 0

Multiply both sides by

100

y^{2} - 2 y - 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 1) = 22

y_{1, 2} = \frac{- ( - 2 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2 2}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2 2}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2 2}{2 \cdot 1} : 1 + 2

y = \frac{- ( - 2 ) - 2 2}{2 \cdot 1} : 1 - 2

The solutions to the quadratic equation are:

y = 1 + 2, y = 1 - 2

3 v^{2} - 48 = 0

x^{2} + 12 x - 364 = 0

x^{2} + 12 x - 3

(a x + 5 b)^{2} - (b x + 5 a)^{2} = 0

x^{2} - 203 x + 252 = 0

What are the solutions to the equation 0.01y^2-0.02y-0.01=0 ?
The solutions to the equation 0.01y^2-0.02y-0.01=0 are y=1+sqrt(2),y=1-sqrt(2)
Find the zeros of 0.01y^2-0.02y-0.01=0
The zeros of 0.01y^2-0.02y-0.01=0 are y=1+sqrt(2),y=1-sqrt(2)