What are the solutions to the equation -2x^2+8x-3=-2x+5 ?

The solutions to the equation -2x^2+8x-3=-2x+5 are x=1,x=4

Find the zeros of -2x^2+8x-3=-2x+5

The zeros of -2x^2+8x-3=-2x+5 are x=1,x=4

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- 2 x^{2} + 8 x - 3 = - 2 x + 5

x = 1, x = 4

Solution steps

- 2 x^{2} + 8 x - 3 = - 2 x + 5

Move

5

to the left side

- 2 x^{2} + 8 x - 8 = - 2 x

Move

2 x

to the left side

- 2 x^{2} + 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

1 0^{2} - 4 (- 2) (- 8) = 6

x_{1, 2} = \frac{- 10 \pm 6}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 6}{2 ( - 2 )}, x_{2} = \frac{- 10 - 6}{2 ( - 2 )}

x = \frac{- 10 + 6}{2 ( - 2 )} : 1

x = \frac{- 10 - 6}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = 1, x = 4

16 x^{2} + 20 x + 4 = 0

- 5 x^{2} + 10 x - 2 = 0

12 x^{2} + 13 x = 14

x^{2} + 25 x + 36 = 0

9 y (1 - y) = 2

What are the solutions to the equation -2x^2+8x-3=-2x+5 ?
The solutions to the equation -2x^2+8x-3=-2x+5 are x=1,x=4
Find the zeros of -2x^2+8x-3=-2x+5
The zeros of -2x^2+8x-3=-2x+5 are x=1,x=4