What are the solutions to the equation 8y+3y^2=35 ?

The solutions to the equation 8y+3y^2=35 are y= 7/3 ,y=-5

Find the zeros of 8y+3y^2=35

The zeros of 8y+3y^2=35 are y= 7/3 ,y=-5

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8 y + 3 y^{2} = 35

y = \frac{7}{3}, y = - 5

Solution steps

8 y + 3 y^{2} = 35

Move

35

to the left side

8 y + 3 y^{2} - 35 = 0

Write in the standard form

a x^{2} + b x + c = 0

3 y^{2} + 8 y - 35 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 35 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 35) = 22

y_{1, 2} = \frac{- 8 \pm 22}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 8 + 22}{2 \cdot 3}, y_{2} = \frac{- 8 - 22}{2 \cdot 3}

y = \frac{- 8 + 22}{2 \cdot 3} : \frac{7}{3}

y = \frac{- 8 - 22}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

y = \frac{7}{3}, y = - 5

- 2 x^{2} + 8 x - 3 = - 2 x + 5

16 x^{2} + 20 x + 4 = 0

- 5 x^{2} + 10 x - 2 = 0

12 x^{2} + 13 x = 14

x^{2} + 25 x + 36 = 0

What are the solutions to the equation 8y+3y^2=35 ?
The solutions to the equation 8y+3y^2=35 are y= 7/3 ,y=-5
Find the zeros of 8y+3y^2=35
The zeros of 8y+3y^2=35 are y= 7/3 ,y=-5