What are the solutions to the equation 4x^2-101x+25=0 ?

The solutions to the equation 4x^2-101x+25=0 are x=25,x= 1/4

Find the zeros of 4x^2-101x+25=0

The zeros of 4x^2-101x+25=0 are x=25,x= 1/4

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4 x^{2} - 101 x + 25 = 0

x = 25, x = \frac{1}{4}

Solution steps

4 x^{2} - 101 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 101 ) \pm ( - 101 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 101)^{2} - 4 \cdot 4 \cdot 25 = 99

x_{1, 2} = \frac{- ( - 101 ) \pm 99}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 101 ) + 99}{2 \cdot 4}, x_{2} = \frac{- ( - 101 ) - 99}{2 \cdot 4}

x = \frac{- ( - 101 ) + 99}{2 \cdot 4} : 25

x = \frac{- ( - 101 ) - 99}{2 \cdot 4} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 25, x = \frac{1}{4}

2 + 6 t - 4.9 t^{2} = 0

(s + 3) (s + 5) = 0

(5 x + 2) (5 x - 2) = (A + B) (A - B)

(x + 2)^{2} = 8 + x

x^{2} - 5 x + 10

What are the solutions to the equation 4x^2-101x+25=0 ?
The solutions to the equation 4x^2-101x+25=0 are x=25,x= 1/4
Find the zeros of 4x^2-101x+25=0
The zeros of 4x^2-101x+25=0 are x=25,x= 1/4