What are the solutions to the equation (s+3)(s+5)=0 ?

The solutions to the equation (s+3)(s+5)=0 are s=-3,s=-5

Find the zeros of (s+3)(s+5)=0

The zeros of (s+3)(s+5)=0 are s=-3,s=-5

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(s + 3) (s + 5) = 0

s = - 3, s = - 5

Solution steps

(s + 3) (s + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s + 3 = 0 or s + 5 = 0

Solve

s + 3 = 0 : s = - 3

Solve

s + 5 = 0 : s = - 5

The solutions to the quadratic equation are:

s = - 3, s = - 5

(5 x + 2) (5 x - 2) = (A + B) (A - B)

(x + 2)^{2} = 8 + x

x^{2} - 5 x + 10

(2 x - 5)^{2} = 7

4 x^{2} + 1 = 7

What are the solutions to the equation (s+3)(s+5)=0 ?
The solutions to the equation (s+3)(s+5)=0 are s=-3,s=-5
Find the zeros of (s+3)(s+5)=0
The zeros of (s+3)(s+5)=0 are s=-3,s=-5