What are the solutions to the equation 2+6t-4.9t^2=0 ?

The solutions to the equation 2+6t-4.9t^2=0 are t=-(2(sqrt(470)-15))/(49),t=(2(15+sqrt(470)))/(49)

Find the zeros of 2+6t-4.9t^2=0

The zeros of 2+6t-4.9t^2=0 are t=-(2(sqrt(470)-15))/(49),t=(2(15+sqrt(470)))/(49)

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2 + 6 t - 4.9 t^{2} = 0

t = - \frac{2 ( 470 - 15 )}{49}, t = \frac{2 ( 15 + 470 )}{49}

Solution steps

2 + 6 t - 4.9 t^{2} = 0

Multiply both sides by

10

20 + 60 t - 49 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 49 t^{2} + 60 t + 20 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 49 ) \cdot 20}{2 ( - 49 )}

6 0^{2} - 4 (- 49) \cdot 20 = 4470

t_{1, 2} = \frac{- 60 \pm 4 470}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 60 + 4 470}{2 ( - 49 )}, t_{2} = \frac{- 60 - 4 470}{2 ( - 49 )}

t = \frac{- 60 + 4 470}{2 ( - 49 )} : - \frac{2 ( 470 - 15 )}{49}

t = \frac{- 60 - 4 470}{2 ( - 49 )} : \frac{2 ( 15 + 470 )}{49}

The solutions to the quadratic equation are:

t = - \frac{2 ( 470 - 15 )}{49}, t = \frac{2 ( 15 + 470 )}{49}

(s + 3) (s + 5) = 0

(5 x + 2) (5 x - 2) = (A + B) (A - B)

(x + 2)^{2} = 8 + x

x^{2} - 5 x + 10

(2 x - 5)^{2} = 7

What are the solutions to the equation 2+6t-4.9t^2=0 ?
The solutions to the equation 2+6t-4.9t^2=0 are t=-(2(sqrt(470)-15))/(49),t=(2(15+sqrt(470)))/(49)
Find the zeros of 2+6t-4.9t^2=0
The zeros of 2+6t-4.9t^2=0 are t=-(2(sqrt(470)-15))/(49),t=(2(15+sqrt(470)))/(49)