What are the solutions to the equation (2x-5)^2=7 ?

The solutions to the equation (2x-5)^2=7 are x=(sqrt(7)+5)/2 ,x=(-sqrt(7)+5)/2

Find the zeros of (2x-5)^2=7

The zeros of (2x-5)^2=7 are x=(sqrt(7)+5)/2 ,x=(-sqrt(7)+5)/2

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(2 x - 5)^{2} = 7

x = \frac{7 + 5}{2}, x = \frac{- 7 + 5}{2}

Solution steps

(2 x - 5)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 7 : x = \frac{7 + 5}{2}

Solve

2 x - 5 = - 7 : x = \frac{- 7 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 5}{2}, x = \frac{- 7 + 5}{2}

4 x^{2} + 1 = 7

2 x^{2} + 15 x - 23 = 2 x

(r - 2) (r + 8) = - 5

h^{2} + 5 h - 700 = 0

6 = 2 (x - 3)^{2} - 1

What are the solutions to the equation (2x-5)^2=7 ?
The solutions to the equation (2x-5)^2=7 are x=(sqrt(7)+5)/2 ,x=(-sqrt(7)+5)/2
Find the zeros of (2x-5)^2=7
The zeros of (2x-5)^2=7 are x=(sqrt(7)+5)/2 ,x=(-sqrt(7)+5)/2