What are the solutions to the equation 4x^2+1=7 ?

The solutions to the equation 4x^2+1=7 are x=sqrt(3/2),x=-sqrt(3/2)

Find the zeros of 4x^2+1=7

The zeros of 4x^2+1=7 are x=sqrt(3/2),x=-sqrt(3/2)

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4 x^{2} + 1 = 7

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 1.22474 \dots, x = - 1.22474 \dots

Solution steps

4 x^{2} + 1 = 7

Move

1

to the right side

4 x^{2} = 6

Divide both sides by

4

x^{2} = \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{2}, x = - \frac{3}{2}

2 x^{2} + 15 x - 23 = 2 x

(r - 2) (r + 8) = - 5

h^{2} + 5 h - 700 = 0

6 = 2 (x - 3)^{2} - 1

b (x) = x^{2} - 4 x

What are the solutions to the equation 4x^2+1=7 ?
The solutions to the equation 4x^2+1=7 are x=sqrt(3/2),x=-sqrt(3/2)
Find the zeros of 4x^2+1=7
The zeros of 4x^2+1=7 are x=sqrt(3/2),x=-sqrt(3/2)