What are the solutions to the equation x^2-20=-8x ?

The solutions to the equation x^2-20=-8x are x=2,x=-10

Find the zeros of x^2-20=-8x

The zeros of x^2-20=-8x are x=2,x=-10

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x^{2} - 20 = - 8 x

x = 2, x = - 10

Solution steps

x^{2} - 20 = - 8 x

Move

8 x

to the left side

x^{2} - 20 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 \cdot 1}, x_{2} = \frac{- 8 - 12}{2 \cdot 1}

x = \frac{- 8 + 12}{2 \cdot 1} : 2

x = \frac{- 8 - 12}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 2, x = - 10

- x^{2} + 2 x = - 3

(x + 1)^{2} - \frac{x + 1}{2} = 18

x^{2} + 7^{2} = 1 2^{2}

16 x^{2} - 40 = 0

4 x (8 x) + 8 - 12 = 15 x^{2} - 12 (25 + 16)

What are the solutions to the equation x^2-20=-8x ?
The solutions to the equation x^2-20=-8x are x=2,x=-10
Find the zeros of x^2-20=-8x
The zeros of x^2-20=-8x are x=2,x=-10