What are the solutions to the equation 2*x^2+x=15 ?

The solutions to the equation 2*x^2+x=15 are x= 5/2 ,x=-3

Find the zeros of 2*x^2+x=15

The zeros of 2*x^2+x=15 are x= 5/2 ,x=-3

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2 \cdot x^{2} + x = 15

x = \frac{5}{2}, x = - 3

Solution steps

2 x^{2} + x = 15

Move

15

to the left side

2 x^{2} + x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 15) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 2}, x_{2} = \frac{- 1 - 11}{2 \cdot 2}

x = \frac{- 1 + 11}{2 \cdot 2} : \frac{5}{2}

x = \frac{- 1 - 11}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 3

4 y - 20 y^{2} = 0

y, x - y^{2} = 1

7 x - 3 + 8 x^{2} = 7 + 4 x^{2} - x

x (x - 6) + 5 (x + 8) = - 2 (3 x - 32)

x^{2} = \frac{81}{100}

What are the solutions to the equation 2*x^2+x=15 ?
The solutions to the equation 2*x^2+x=15 are x= 5/2 ,x=-3
Find the zeros of 2*x^2+x=15
The zeros of 2*x^2+x=15 are x= 5/2 ,x=-3