What are the solutions to the equation 4y-20y^2=0 ?

The solutions to the equation 4y-20y^2=0 are y=0,y= 1/5

Find the zeros of 4y-20y^2=0

The zeros of 4y-20y^2=0 are y=0,y= 1/5

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4 y - 20 y^{2} = 0

y = 0, y = \frac{1}{5}

Solution steps

4 y - 20 y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 20 y^{2} + 4 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 20 ) \cdot 0}{2 ( - 20 )}

4^{2} - 4 (- 20) \cdot 0 = 4

y_{1, 2} = \frac{- 4 \pm 4}{2 ( - 20 )}

Separate the solutions

y_{1} = \frac{- 4 + 4}{2 ( - 20 )}, y_{2} = \frac{- 4 - 4}{2 ( - 20 )}

y = \frac{- 4 + 4}{2 ( - 20 )} : 0

y = \frac{- 4 - 4}{2 ( - 20 )} : \frac{1}{5}

The solutions to the quadratic equation are:

y = 0, y = \frac{1}{5}

y, x - y^{2} = 1

7 x - 3 + 8 x^{2} = 7 + 4 x^{2} - x

x (x - 6) + 5 (x + 8) = - 2 (3 x - 32)

x^{2} = \frac{81}{100}

x, x^{2} - 9 x + 20 = y

What are the solutions to the equation 4y-20y^2=0 ?
The solutions to the equation 4y-20y^2=0 are y=0,y= 1/5
Find the zeros of 4y-20y^2=0
The zeros of 4y-20y^2=0 are y=0,y= 1/5