What are the solutions to the equation x^2+2x^2=16 ?

The solutions to the equation x^2+2x^2=16 are x= 4/(sqrt(3)),x=-4/(sqrt(3))

Find the zeros of x^2+2x^2=16

The zeros of x^2+2x^2=16 are x= 4/(sqrt(3)),x=-4/(sqrt(3))

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x^{2} + 2 x^{2} = 16

x = \frac{4}{3}, x = - \frac{4}{3}

Decimal Notation

x = 2.30940 \dots, x = - 2.30940 \dots

Solution steps

x^{2} + 2 x^{2} = 16

Add similar elements:

x^{2} + 2 x^{2} = 3 x^{2}

3 x^{2} = 16

Divide both sides by

3

x^{2} = \frac{16}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{3}, x = - \frac{16}{3}

\frac{16}{3} = \frac{4}{3}

- \frac{16}{3} = - \frac{4}{3}

x = \frac{4}{3}, x = - \frac{4}{3}

- 72 (1 + x)^{(2)} + 170 (1 + x) + 100 = 0

x, 2 x^{2} - 4 x = 0

12 x^{2} + 12 = 0

- 6 x^{2} + 24 x - 504 = 0

15 x^{2} - 23 x - 28 = 0

What are the solutions to the equation x^2+2x^2=16 ?
The solutions to the equation x^2+2x^2=16 are x= 4/(sqrt(3)),x=-4/(sqrt(3))
Find the zeros of x^2+2x^2=16
The zeros of x^2+2x^2=16 are x= 4/(sqrt(3)),x=-4/(sqrt(3))