What are the solutions to the equation x^2+18=-6x ?

The solutions to the equation x^2+18=-6x are x=-3+3i,x=-3-3i

Find the zeros of x^2+18=-6x

The zeros of x^2+18=-6x are x=-3+3i,x=-3-3i

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x^{2} + 18 = - 6 x

x = - 3 + 3 i, x = - 3 - 3 i

Solution steps

x^{2} + 18 = - 6 x

Move

6 x

to the left side

x^{2} + 18 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 6 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 18 : 6 i

x_{1, 2} = \frac{- 6 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 6 i}{2 \cdot 1}

x = \frac{- 6 + 6 i}{2 \cdot 1} : - 3 + 3 i

x = \frac{- 6 - 6 i}{2 \cdot 1} : - 3 - 3 i

The solutions to the quadratic equation are:

x = - 3 + 3 i, x = - 3 - 3 i

- 4 x^{2} = - 8

x^{2} + 2 x^{2} = 16

- 72 (1 + x)^{(2)} + 170 (1 + x) + 100 = 0

x, 2 x^{2} - 4 x = 0

12 x^{2} + 12 = 0

What are the solutions to the equation x^2+18=-6x ?
The solutions to the equation x^2+18=-6x are x=-3+3i,x=-3-3i
Find the zeros of x^2+18=-6x
The zeros of x^2+18=-6x are x=-3+3i,x=-3-3i