What are the solutions to the equation 12x^2+12=0 ?

The solutions to the equation 12x^2+12=0 are x=i,x=-i

Find the zeros of 12x^2+12=0

The zeros of 12x^2+12=0 are x=i,x=-i

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12 x^{2} + 12 = 0

x = i, x = - i

Solution steps

12 x^{2} + 12 = 0

Move

12

to the right side

12 x^{2} = - 12

Divide both sides by

12

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

- 6 x^{2} + 24 x - 504 = 0

15 x^{2} - 23 x - 28 = 0

150 = 50 x + x^{2}

j (x) = x^{2} - x + 1, j (2 a)

x, x^{2} + 2 x^{2} y + 3 x y = 0

What are the solutions to the equation 12x^2+12=0 ?
The solutions to the equation 12x^2+12=0 are x=i,x=-i
Find the zeros of 12x^2+12=0
The zeros of 12x^2+12=0 are x=i,x=-i