What are the solutions to the equation (x^2+3x+2)2-8(x^2+3x)=4 ?

The solutions to the equation (x^2+3x+2)2-8(x^2+3x)=4 are x=-3,x=0

Find the zeros of (x^2+3x+2)2-8(x^2+3x)=4

The zeros of (x^2+3x+2)2-8(x^2+3x)=4 are x=-3,x=0

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(x^{2} + 3 x + 2) 2 - 8 (x^{2} + 3 x) = 4

x = - 3, x = 0

Solution steps

(x^{2} + 3 x + 2) \cdot 2 - 8 (x^{2} + 3 x) = 4

Expand

(x^{2} + 3 x + 2) \cdot 2 - 8 (x^{2} + 3 x) : - 6 x^{2} - 18 x + 4

- 6 x^{2} - 18 x + 4 = 4

Move

4

to the left side

- 6 x^{2} - 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

(- 18)^{2} - 4 (- 6) \cdot 0 = 18

x_{1, 2} = \frac{- ( - 18 ) \pm 18}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 18}{2 ( - 6 )}, x_{2} = \frac{- ( - 18 ) - 18}{2 ( - 6 )}

x = \frac{- ( - 18 ) + 18}{2 ( - 6 )} : - 3

x = \frac{- ( - 18 ) - 18}{2 ( - 6 )} : 0

The solutions to the quadratic equation are:

x = - 3, x = 0

2 x^{2} + 3 = 49

2 x^{2} + 3 = 2 x

7 x^{2} - 10 = x^{2} - 4

x (3 x) = 550

x^{2} + 89 = 20 x

What are the solutions to the equation (x^2+3x+2)2-8(x^2+3x)=4 ?
The solutions to the equation (x^2+3x+2)2-8(x^2+3x)=4 are x=-3,x=0
Find the zeros of (x^2+3x+2)2-8(x^2+3x)=4
The zeros of (x^2+3x+2)2-8(x^2+3x)=4 are x=-3,x=0