What are the solutions to the equation 2x^2+3=49 ?

The solutions to the equation 2x^2+3=49 are x=sqrt(23),x=-sqrt(23)

Find the zeros of 2x^2+3=49

The zeros of 2x^2+3=49 are x=sqrt(23),x=-sqrt(23)

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2 x^{2} + 3 = 49

x = 23, x = - 23

Solution steps

2 x^{2} + 3 = 49

Move

3

to the right side

2 x^{2} = 46

Divide both sides by

2

x^{2} = 23

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 23, x = - 23

2 x^{2} + 3 = 2 x

7 x^{2} - 10 = x^{2} - 4

x (3 x) = 550

x^{2} + 89 = 20 x

(k - 13)^{2} - 324 = 0

What are the solutions to the equation 2x^2+3=49 ?
The solutions to the equation 2x^2+3=49 are x=sqrt(23),x=-sqrt(23)
Find the zeros of 2x^2+3=49
The zeros of 2x^2+3=49 are x=sqrt(23),x=-sqrt(23)