What are the solutions to the equation x^2+89=20x ?

The solutions to the equation x^2+89=20x are x=10+sqrt(11),x=10-sqrt(11)

Find the zeros of x^2+89=20x

The zeros of x^2+89=20x are x=10+sqrt(11),x=10-sqrt(11)

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x^{2} + 89 = 20 x

x = 10 + 11, x = 10 - 11

Solution steps

x^{2} + 89 = 20 x

Move

20 x

to the left side

x^{2} + 89 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 20 x + 89 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 89}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 89 = 211

x_{1, 2} = \frac{- ( - 20 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 11}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 11}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 11}{2 \cdot 1} : 10 + 11

x = \frac{- ( - 20 ) - 2 11}{2 \cdot 1} : 10 - 11

The solutions to the quadratic equation are:

x = 10 + 11, x = 10 - 11

(k - 13)^{2} - 324 = 0

11 x^{2} - 12 x + 1 = 0

x^{2} + 20 x - 200 = 0

3 x^{2} - 2 x - 1 = 0

5 x^{2} + 4 x = 3

What are the solutions to the equation x^2+89=20x ?
The solutions to the equation x^2+89=20x are x=10+sqrt(11),x=10-sqrt(11)
Find the zeros of x^2+89=20x
The zeros of x^2+89=20x are x=10+sqrt(11),x=10-sqrt(11)