What are the solutions to the equation 7x^2-10=x^2-4 ?

The solutions to the equation 7x^2-10=x^2-4 are x=1,x=-1

Find the zeros of 7x^2-10=x^2-4

The zeros of 7x^2-10=x^2-4 are x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 x^{2} - 10 = x^{2} - 4

x = 1, x = - 1

Solution steps

7 x^{2} - 10 = x^{2} - 4

Move

10

to the right side

7 x^{2} = x^{2} + 6

Move

x^{2}

to the left side

6 x^{2} = 6

Divide both sides by

6

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

x (3 x) = 550

x^{2} + 89 = 20 x

(k - 13)^{2} - 324 = 0

11 x^{2} - 12 x + 1 = 0

x^{2} + 20 x - 200 = 0

What are the solutions to the equation 7x^2-10=x^2-4 ?
The solutions to the equation 7x^2-10=x^2-4 are x=1,x=-1
Find the zeros of 7x^2-10=x^2-4
The zeros of 7x^2-10=x^2-4 are x=1,x=-1