What are the solutions to the equation x^2-1=6x ?

The solutions to the equation x^2-1=6x are x=3+sqrt(10),x=3-sqrt(10)

Find the zeros of x^2-1=6x

The zeros of x^2-1=6x are x=3+sqrt(10),x=3-sqrt(10)

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x^{2} - 1 = 6 x

x = 3 + 10, x = 3 - 10

Solution steps

x^{2} - 1 = 6 x

Move

6 x

to the left side

x^{2} - 1 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 1) = 210

x_{1, 2} = \frac{- ( - 6 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 10}{2 \cdot 1} : 3 + 10

x = \frac{- ( - 6 ) - 2 10}{2 \cdot 1} : 3 - 10

The solutions to the quadratic equation are:

x = 3 + 10, x = 3 - 10

3 x - 2 x^{2} - 7 = 0

d^{2} = \frac{6 \cdot 4}{31415}

2 x^{2} + 4 x - 1 = 0

x^{2} + 1 - 3 x = 0

2 f (a) = 3 x^{2} - x + 2

What are the solutions to the equation x^2-1=6x ?
The solutions to the equation x^2-1=6x are x=3+sqrt(10),x=3-sqrt(10)
Find the zeros of x^2-1=6x
The zeros of x^2-1=6x are x=3+sqrt(10),x=3-sqrt(10)