What are the solutions to the equation (5/13)^2+x^2=1 ?

The solutions to the equation (5/13)^2+x^2=1 are x= 12/13 ,x=-12/13

Find the zeros of (5/13)^2+x^2=1

The zeros of (5/13)^2+x^2=1 are x= 12/13 ,x=-12/13

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(\frac{5}{13})^{2} + x^{2} = 1

x = \frac{12}{13}, x = - \frac{12}{13}

Decimal Notation

x = 0.92307 \dots, x = - 0.92307 \dots

Solution steps

(\frac{5}{13})^{2} + x^{2} = 1

Expand

(\frac{5}{13})^{2} + x^{2} : \frac{25}{169} + x^{2}

\frac{25}{169} + x^{2} = 1

Move

\frac{25}{169}

to the right side

x^{2} = 1 - \frac{25}{169}

Simplify

1 - \frac{25}{169} : \frac{144}{169}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{144}{169}, x = - \frac{144}{169}

\frac{144}{169} = \frac{12}{13}

- \frac{144}{169} = - \frac{12}{13}

x = \frac{12}{13}, x = - \frac{12}{13}

6 s^{2} + 18 s = 0

5 x^{2} - 72 = 4 x^{2}

x^{2} - 16 x + 2 = 0

3 x^{2} - 3 = 8 x

(3 x + 4)^{2} - 6 (3 x + 4) + 9 = 0

What are the solutions to the equation (5/13)^2+x^2=1 ?
The solutions to the equation (5/13)^2+x^2=1 are x= 12/13 ,x=-12/13
Find the zeros of (5/13)^2+x^2=1
The zeros of (5/13)^2+x^2=1 are x= 12/13 ,x=-12/13