What are the solutions to the equation 3x^2-3=8x ?

The solutions to the equation 3x^2-3=8x are x=3,x=-1/3

Find the zeros of 3x^2-3=8x

The zeros of 3x^2-3=8x are x=3,x=-1/3

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3 x^{2} - 3 = 8 x

x = 3, x = - \frac{1}{3}

Solution steps

3 x^{2} - 3 = 8 x

Move

8 x

to the left side

3 x^{2} - 3 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 3) = 10

x_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 3}

x = \frac{- ( - 8 ) + 10}{2 \cdot 3} : 3

x = \frac{- ( - 8 ) - 10}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{3}

(3 x + 4)^{2} - 6 (3 x + 4) + 9 = 0

1 + 8 x - 0.6 x^{2} = 1 + 4 x - 0.2 x^{2}

y^{2} = 6 - 0

- x^{2} + 40 x - 1200 = 0

\frac{1}{7} x^{2} - 3 = 4

What are the solutions to the equation 3x^2-3=8x ?
The solutions to the equation 3x^2-3=8x are x=3,x=-1/3
Find the zeros of 3x^2-3=8x
The zeros of 3x^2-3=8x are x=3,x=-1/3