What are the solutions to the equation (3x+4)^2-6(3x+4)+9=0 ?

The solutions to the equation (3x+4)^2-6(3x+4)+9=0 are x=-1/3

Find the zeros of (3x+4)^2-6(3x+4)+9=0

The zeros of (3x+4)^2-6(3x+4)+9=0 are x=-1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x + 4)^{2} - 6 (3 x + 4) + 9 = 0

x = - \frac{1}{3}

Solution steps

(3 x + 4)^{2} - 6 (3 x + 4) + 9 = 0

Expand

(3 x + 4)^{2} - 6 (3 x + 4) + 9 : 9 x^{2} + 6 x + 1

9 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

x = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

x = - \frac{1}{3}

The solution to the quadratic equation is:

x = - \frac{1}{3}

1 + 8 x - 0.6 x^{2} = 1 + 4 x - 0.2 x^{2}

y^{2} = 6 - 0

- x^{2} + 40 x - 1200 = 0

\frac{1}{7} x^{2} - 3 = 4

x, y = x^{2} - 20 x

What are the solutions to the equation (3x+4)^2-6(3x+4)+9=0 ?
The solutions to the equation (3x+4)^2-6(3x+4)+9=0 are x=-1/3
Find the zeros of (3x+4)^2-6(3x+4)+9=0
The zeros of (3x+4)^2-6(3x+4)+9=0 are x=-1/3