What are the solutions to the equation 81r^2-3=0 ?

The solutions to the equation 81r^2-3=0 are r= 1/(3sqrt(3)),r=-1/(3sqrt(3))

Find the zeros of 81r^2-3=0

The zeros of 81r^2-3=0 are r= 1/(3sqrt(3)),r=-1/(3sqrt(3))

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81 r^{2} - 3 = 0

r = \frac{1}{3 3}, r = - \frac{1}{3 3}

Solution steps

81 r^{2} - 3 = 0

Move

3

to the right side

81 r^{2} = 3

Divide both sides by

81

r^{2} = \frac{1}{27}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{1}{27}, r = - \frac{1}{27}

\frac{1}{27} = \frac{1}{3 3}

- \frac{1}{27} = - \frac{1}{3 3}

r = \frac{1}{3 3}, r = - \frac{1}{3 3}

(7 - 3 x)^{2} = \frac{9}{16}

2 m^{2} + 3 m + 4 = 0

2 x^{2} + 16 x - 9 = 0

6 x - 27 = - x^{2}

2 x^{2} + 8 x + 10 = 4

What are the solutions to the equation 81r^2-3=0 ?
The solutions to the equation 81r^2-3=0 are r= 1/(3sqrt(3)),r=-1/(3sqrt(3))
Find the zeros of 81r^2-3=0
The zeros of 81r^2-3=0 are r= 1/(3sqrt(3)),r=-1/(3sqrt(3))