What are the solutions to the equation 2m^2+3m+4=0 ?

The solutions to the equation 2m^2+3m+4=0 are m=-3/4+i(sqrt(23))/4 ,m=-3/4-i(sqrt(23))/4

Find the zeros of 2m^2+3m+4=0

The zeros of 2m^2+3m+4=0 are m=-3/4+i(sqrt(23))/4 ,m=-3/4-i(sqrt(23))/4

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2 m^{2} + 3 m + 4 = 0

m = - \frac{3}{4} + i \frac{23}{4}, m = - \frac{3}{4} - i \frac{23}{4}

Solution steps

2 m^{2} + 3 m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 4 : 23 i

m_{1, 2} = \frac{- 3 \pm 23 i}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 3 + 23 i}{2 \cdot 2}, m_{2} = \frac{- 3 - 23 i}{2 \cdot 2}

m = \frac{- 3 + 23 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{23}{4}

m = \frac{- 3 - 23 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{23}{4}

The solutions to the quadratic equation are:

m = - \frac{3}{4} + i \frac{23}{4}, m = - \frac{3}{4} - i \frac{23}{4}

2 x^{2} + 16 x - 9 = 0

6 x - 27 = - x^{2}

2 x^{2} + 8 x + 10 = 4

6 x^{2} - x - 7 = 0

(x + 3)^{2} - 5 = 11

What are the solutions to the equation 2m^2+3m+4=0 ?
The solutions to the equation 2m^2+3m+4=0 are m=-3/4+i(sqrt(23))/4 ,m=-3/4-i(sqrt(23))/4
Find the zeros of 2m^2+3m+4=0
The zeros of 2m^2+3m+4=0 are m=-3/4+i(sqrt(23))/4 ,m=-3/4-i(sqrt(23))/4