What are the solutions to the equation 2x^2+8x+10=4 ?

The solutions to the equation 2x^2+8x+10=4 are x=-1,x=-3

Find the zeros of 2x^2+8x+10=4

The zeros of 2x^2+8x+10=4 are x=-1,x=-3

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2 x^{2} + 8 x + 10 = 4

x = - 1, x = - 3

Solution steps

2 x^{2} + 8 x + 10 = 4

Move

4

to the left side

2 x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 6 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 2}, x_{2} = \frac{- 8 - 4}{2 \cdot 2}

x = \frac{- 8 + 4}{2 \cdot 2} : - 1

x = \frac{- 8 - 4}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

6 x^{2} - x - 7 = 0

(x + 3)^{2} - 5 = 11

(3 - x) (- 1 - x) - 5 = 0

x^{2} + 25 x + 150 = 0

(4 x + 5)^{2} = 5

What are the solutions to the equation 2x^2+8x+10=4 ?
The solutions to the equation 2x^2+8x+10=4 are x=-1,x=-3
Find the zeros of 2x^2+8x+10=4
The zeros of 2x^2+8x+10=4 are x=-1,x=-3