What are the solutions to the equation 6x^2-x-7=0 ?

The solutions to the equation 6x^2-x-7=0 are x= 7/6 ,x=-1

Find the zeros of 6x^2-x-7=0

The zeros of 6x^2-x-7=0 are x= 7/6 ,x=-1

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6 x^{2} - x - 7 = 0

x = \frac{7}{6}, x = - 1

Solution steps

6 x^{2} - x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 7) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 6}

x = \frac{- ( - 1 ) + 13}{2 \cdot 6} : \frac{7}{6}

x = \frac{- ( - 1 ) - 13}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

x = \frac{7}{6}, x = - 1

(x + 3)^{2} - 5 = 11

(3 - x) (- 1 - x) - 5 = 0

x^{2} + 25 x + 150 = 0

(4 x + 5)^{2} = 5

(m + 3) (m - 3) = 0

What are the solutions to the equation 6x^2-x-7=0 ?
The solutions to the equation 6x^2-x-7=0 are x= 7/6 ,x=-1
Find the zeros of 6x^2-x-7=0
The zeros of 6x^2-x-7=0 are x= 7/6 ,x=-1