What are the solutions to the equation (x+3)^2-5=11 ?

The solutions to the equation (x+3)^2-5=11 are x=1,x=-7

Find the zeros of (x+3)^2-5=11

The zeros of (x+3)^2-5=11 are x=1,x=-7

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(x + 3)^{2} - 5 = 11

x = 1, x = - 7

Solution steps

(x + 3)^{2} - 5 = 11

Move

5

to the right side

(x + 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 16 : x = 1

Solve

x + 3 = - 16 : x = - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

(3 - x) (- 1 - x) - 5 = 0

x^{2} + 25 x + 150 = 0

(4 x + 5)^{2} = 5

(m + 3) (m - 3) = 0

207 = 2 x^{2} + 7

What are the solutions to the equation (x+3)^2-5=11 ?
The solutions to the equation (x+3)^2-5=11 are x=1,x=-7
Find the zeros of (x+3)^2-5=11
The zeros of (x+3)^2-5=11 are x=1,x=-7