What are the solutions to the equation (4x+5)^2=5 ?

The solutions to the equation (4x+5)^2=5 are x=(sqrt(5)-5)/4 ,x=(-sqrt(5)-5)/4

Find the zeros of (4x+5)^2=5

The zeros of (4x+5)^2=5 are x=(sqrt(5)-5)/4 ,x=(-sqrt(5)-5)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(4 x + 5)^{2} = 5

x = \frac{5 - 5}{4}, x = \frac{- 5 - 5}{4}

Solution steps

(4 x + 5)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 5 = 5 : x = \frac{5 - 5}{4}

Solve

4 x + 5 = - 5 : x = \frac{- 5 - 5}{4}

The solutions to the quadratic equation are:

x = \frac{5 - 5}{4}, x = \frac{- 5 - 5}{4}

(m + 3) (m - 3) = 0

207 = 2 x^{2} + 7

x, f^{- 1} (x) = x^{2} + 4 x

- 3 x^{2} + 30 x = 0

- 0.25 x^{2} + 350 x - 120000 = 0

What are the solutions to the equation (4x+5)^2=5 ?
The solutions to the equation (4x+5)^2=5 are x=(sqrt(5)-5)/4 ,x=(-sqrt(5)-5)/4
Find the zeros of (4x+5)^2=5
The zeros of (4x+5)^2=5 are x=(sqrt(5)-5)/4 ,x=(-sqrt(5)-5)/4