What are the solutions to the equation 2x^2+5=25 ?

The solutions to the equation 2x^2+5=25 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 2x^2+5=25

The zeros of 2x^2+5=25 are x=sqrt(10),x=-sqrt(10)

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2 x^{2} + 5 = 25

x = 10, x = - 10

Solution steps

2 x^{2} + 5 = 25

Move

5

to the right side

2 x^{2} = 20

Divide both sides by

2

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

x^{2} + 16 x - 57 = 0

x, 6 x^{2} + 12 x + 5 = 0

x, f (x + 1) = x^{2} - 3 x + 2

x, 3 x^{2} = - 8 x - 5

4 x^{2} + 145 = 4 x

What are the solutions to the equation 2x^2+5=25 ?
The solutions to the equation 2x^2+5=25 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 2x^2+5=25
The zeros of 2x^2+5=25 are x=sqrt(10),x=-sqrt(10)