What are the solutions to the equation x^2+16x-57=0 ?

The solutions to the equation x^2+16x-57=0 are x=3,x=-19

Find the zeros of x^2+16x-57=0

The zeros of x^2+16x-57=0 are x=3,x=-19

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x^{2} + 16 x - 57 = 0

x = 3, x = - 19

Solution steps

x^{2} + 16 x - 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 57 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 57) = 22

x_{1, 2} = \frac{- 16 \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 22}{2 \cdot 1}, x_{2} = \frac{- 16 - 22}{2 \cdot 1}

x = \frac{- 16 + 22}{2 \cdot 1} : 3

x = \frac{- 16 - 22}{2 \cdot 1} : - 19

The solutions to the quadratic equation are:

x = 3, x = - 19

x, 6 x^{2} + 12 x + 5 = 0

x, f (x + 1) = x^{2} - 3 x + 2

x, 3 x^{2} = - 8 x - 5

4 x^{2} + 145 = 4 x

(r - 5)^{2} = 40

What are the solutions to the equation x^2+16x-57=0 ?
The solutions to the equation x^2+16x-57=0 are x=3,x=-19
Find the zeros of x^2+16x-57=0
The zeros of x^2+16x-57=0 are x=3,x=-19