What are the solutions to the equation 4x^2+145=4x ?

The solutions to the equation 4x^2+145=4x are x= 1/2+6i,x= 1/2-6i

Find the zeros of 4x^2+145=4x

The zeros of 4x^2+145=4x are x= 1/2+6i,x= 1/2-6i

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4 x^{2} + 145 = 4 x

x = \frac{1}{2} + 6 i, x = \frac{1}{2} - 6 i

Solution steps

4 x^{2} + 145 = 4 x

Move

4 x

to the left side

4 x^{2} + 145 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 145 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 145}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 145 : 48 i

x_{1, 2} = \frac{- ( - 4 ) \pm 48 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 48 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 48 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 48 i}{2 \cdot 4} : \frac{1}{2} + 6 i

x = \frac{- ( - 4 ) - 48 i}{2 \cdot 4} : \frac{1}{2} - 6 i

The solutions to the quadratic equation are:

x = \frac{1}{2} + 6 i, x = \frac{1}{2} - 6 i

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2 x^{2} - x - 10 = 0

2 x^{2} + 7 x + 6 = 0

x^{2} + 3 x + 30 = 0

(x - 7) (5 x + 8) = 0

What are the solutions to the equation 4x^2+145=4x ?
The solutions to the equation 4x^2+145=4x are x= 1/2+6i,x= 1/2-6i
Find the zeros of 4x^2+145=4x
The zeros of 4x^2+145=4x are x= 1/2+6i,x= 1/2-6i