What are the solutions to the equation 3x^2+60=36x ?

The solutions to the equation 3x^2+60=36x are x=10,x=2

Find the zeros of 3x^2+60=36x

The zeros of 3x^2+60=36x are x=10,x=2

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3 x^{2} + 60 = 36 x

x = 10, x = 2

Solution steps

3 x^{2} + 60 = 36 x

Move

36 x

to the left side

3 x^{2} + 60 - 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 36 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 \cdot 60}{2 \cdot 3}

(- 36)^{2} - 4 \cdot 3 \cdot 60 = 24

x_{1, 2} = \frac{- ( - 36 ) \pm 24}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 24}{2 \cdot 3}, x_{2} = \frac{- ( - 36 ) - 24}{2 \cdot 3}

x = \frac{- ( - 36 ) + 24}{2 \cdot 3} : 10

x = \frac{- ( - 36 ) - 24}{2 \cdot 3} : 2

The solutions to the quadratic equation are:

x = 10, x = 2

49 x^{2} + 70 x + 25 = 0

a^{2} + 3 a + 2 = 0

a x^{2} + b x + c = (5 x - 6) (2 x - 1)

3 x^{2} + 3 x + 8 = 0

5 x^{2} + 8 x - 2 = 0

What are the solutions to the equation 3x^2+60=36x ?
The solutions to the equation 3x^2+60=36x are x=10,x=2
Find the zeros of 3x^2+60=36x
The zeros of 3x^2+60=36x are x=10,x=2