What are the solutions to the equation completesquare 6x^2-3x=0 ?

The solutions to the equation completesquare 6x^2-3x=0 are x= 1/2 ,x=0

Find the zeros of completesquare 6x^2-3x=0

The zeros of completesquare 6x^2-3x=0 are x= 1/2 ,x=0

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6 x^{2} - 3 x = 0

x = \frac{1}{2}, x = 0

Solution steps

6 x^{2} - 3 x = 0

Divide both sides by

6

\frac{6 x ^{2} - 3 x}{6} = \frac{0}{6}

x^{2} - \frac{x}{2} = 0

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{4})^{2} = \frac{1}{16}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{1}{4} = \frac{1}{16} : x = \frac{1}{2}

Solve

x - \frac{1}{4} = - \frac{1}{16} : x = 0

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 0

7 x^{2} - 15 x + 8 = 0

2 t (t + 1) = 7

r, y = 4 π r^{2}

x^{2} - 3 \cdot (- 10) = 0

v, F = \frac{d M v ^{2}}{r}

What are the solutions to the equation completesquare 6x^2-3x=0 ?
The solutions to the equation completesquare 6x^2-3x=0 are x= 1/2 ,x=0
Find the zeros of completesquare 6x^2-3x=0
The zeros of completesquare 6x^2-3x=0 are x= 1/2 ,x=0