What are the solutions to the equation z^2+24z+140=0 ?

The solutions to the equation z^2+24z+140=0 are z=-10,z=-14

Find the zeros of z^2+24z+140=0

The zeros of z^2+24z+140=0 are z=-10,z=-14

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z^{2} + 24 z + 140 = 0

z = - 10, z = - 14

Solution steps

z^{2} + 24 z + 140 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 140}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot 140 = 4

z_{1, 2} = \frac{- 24 \pm 4}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 24 + 4}{2 \cdot 1}, z_{2} = \frac{- 24 - 4}{2 \cdot 1}

z = \frac{- 24 + 4}{2 \cdot 1} : - 10

z = \frac{- 24 - 4}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

z = - 10, z = - 14

98 x^{2} - 2 = 0

6 x^{2} + 2 = 34

\frac{( x + 4 ) ( x - 2 )}{4} = 10

3 x^{2} + 5 x = 2 (2 - 3 x)

2 ((0 - 3)^{2} + (y + 2)^{2}) = 50

What are the solutions to the equation z^2+24z+140=0 ?
The solutions to the equation z^2+24z+140=0 are z=-10,z=-14
Find the zeros of z^2+24z+140=0
The zeros of z^2+24z+140=0 are z=-10,z=-14