What are the solutions to the equation ((x+4)(x-2))/4 =10 ?

The solutions to the equation ((x+4)(x-2))/4 =10 are x=6,x=-8

Find the zeros of ((x+4)(x-2))/4 =10

The zeros of ((x+4)(x-2))/4 =10 are x=6,x=-8

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\frac{( x + 4 ) ( x - 2 )}{4} = 10

x = 6, x = - 8

Solution steps

\frac{( x + 4 ) ( x - 2 )}{4} = 10

Multiply both sides by

4

(x + 4) (x - 2) = 40

Expand

(x + 4) (x - 2) : x^{2} + 2 x - 8

x^{2} + 2 x - 8 = 40

Move

40

to the left side

x^{2} + 2 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 48) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 1}, x_{2} = \frac{- 2 - 14}{2 \cdot 1}

x = \frac{- 2 + 14}{2 \cdot 1} : 6

x = \frac{- 2 - 14}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 6, x = - 8

3 x^{2} + 5 x = 2 (2 - 3 x)

2 ((0 - 3)^{2} + (y + 2)^{2}) = 50

10 x^{2} = 23 x + 5

12 x^{2} + 96 x = 0

3 n^{2} + 12 n - 15 = 0

What are the solutions to the equation ((x+4)(x-2))/4 =10 ?
The solutions to the equation ((x+4)(x-2))/4 =10 are x=6,x=-8
Find the zeros of ((x+4)(x-2))/4 =10
The zeros of ((x+4)(x-2))/4 =10 are x=6,x=-8