What are the solutions to the equation 6x^2+2=34 ?

The solutions to the equation 6x^2+2=34 are x= 4/(sqrt(3)),x=-4/(sqrt(3))

Find the zeros of 6x^2+2=34

The zeros of 6x^2+2=34 are x= 4/(sqrt(3)),x=-4/(sqrt(3))

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6 x^{2} + 2 = 34

x = \frac{4}{3}, x = - \frac{4}{3}

Decimal Notation

x = 2.30940 \dots, x = - 2.30940 \dots

Solution steps

6 x^{2} + 2 = 34

Move

2

to the right side

6 x^{2} = 32

Divide both sides by

6

x^{2} = \frac{16}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{3}, x = - \frac{16}{3}

\frac{16}{3} = \frac{4}{3}

- \frac{16}{3} = - \frac{4}{3}

x = \frac{4}{3}, x = - \frac{4}{3}

\frac{( x + 4 ) ( x - 2 )}{4} = 10

3 x^{2} + 5 x = 2 (2 - 3 x)

2 ((0 - 3)^{2} + (y + 2)^{2}) = 50

10 x^{2} = 23 x + 5

12 x^{2} + 96 x = 0

What are the solutions to the equation 6x^2+2=34 ?
The solutions to the equation 6x^2+2=34 are x= 4/(sqrt(3)),x=-4/(sqrt(3))
Find the zeros of 6x^2+2=34
The zeros of 6x^2+2=34 are x= 4/(sqrt(3)),x=-4/(sqrt(3))