What are the solutions to the equation 5x^2+11x-1=0 ?

The solutions to the equation 5x^2+11x-1=0 are x=(-11+sqrt(141))/(10),x=(-11-sqrt(141))/(10)

Find the zeros of 5x^2+11x-1=0

The zeros of 5x^2+11x-1=0 are x=(-11+sqrt(141))/(10),x=(-11-sqrt(141))/(10)

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5 x^{2} + 11 x - 1 = 0

x = \frac{- 11 + 141}{10}, x = \frac{- 11 - 141}{10}

Solution steps

5 x^{2} + 11 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

1 1^{2} - 4 \cdot 5 (- 1) = 141

x_{1, 2} = \frac{- 11 \pm 141}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 11 + 141}{2 \cdot 5}, x_{2} = \frac{- 11 - 141}{2 \cdot 5}

x = \frac{- 11 + 141}{2 \cdot 5} : \frac{- 11 + 141}{10}

x = \frac{- 11 - 141}{2 \cdot 5} : \frac{- 11 - 141}{10}

The solutions to the quadratic equation are:

x = \frac{- 11 + 141}{10}, x = \frac{- 11 - 141}{10}

x^{2} + 4 x = 0

- x^{2} + 8 x - 5

x^{2} + 22 x - 5 = 0

x^{2} - 126 = 2 x + 1

60 = 50 + 20 \cdot t - 5 \cdot t^{2}

What are the solutions to the equation 5x^2+11x-1=0 ?
The solutions to the equation 5x^2+11x-1=0 are x=(-11+sqrt(141))/(10),x=(-11-sqrt(141))/(10)
Find the zeros of 5x^2+11x-1=0
The zeros of 5x^2+11x-1=0 are x=(-11+sqrt(141))/(10),x=(-11-sqrt(141))/(10)