What are the solutions to the equation 6x^2+3=7x ?

The solutions to the equation 6x^2+3=7x are x= 7/12+i(sqrt(23))/(12),x= 7/12-i(sqrt(23))/(12)

Find the zeros of 6x^2+3=7x

The zeros of 6x^2+3=7x are x= 7/12+i(sqrt(23))/(12),x= 7/12-i(sqrt(23))/(12)

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6 x^{2} + 3 = 7 x

x = \frac{7}{12} + i \frac{23}{12}, x = \frac{7}{12} - i \frac{23}{12}

Solution steps

6 x^{2} + 3 = 7 x

Move

7 x

to the left side

6 x^{2} + 3 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

Simplify

(- 7)^{2} - 4 \cdot 6 \cdot 3 : 23 i

x_{1, 2} = \frac{- ( - 7 ) \pm 23 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 23 i}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 23 i}{2 \cdot 6}

x = \frac{- ( - 7 ) + 23 i}{2 \cdot 6} : \frac{7}{12} + i \frac{23}{12}

x = \frac{- ( - 7 ) - 23 i}{2 \cdot 6} : \frac{7}{12} - i \frac{23}{12}

The solutions to the quadratic equation are:

x = \frac{7}{12} + i \frac{23}{12}, x = \frac{7}{12} - i \frac{23}{12}

x^{2} + 4 x + 3 = 195

3 x^{2} + 4 x - 32 = 0

x, 7 x^{2} + 8 x - 9 = 10

x^{2} - 7 = - 3 x^{2}

6 y^{2} - y + 2 = 0

What are the solutions to the equation 6x^2+3=7x ?
The solutions to the equation 6x^2+3=7x are x= 7/12+i(sqrt(23))/(12),x= 7/12-i(sqrt(23))/(12)
Find the zeros of 6x^2+3=7x
The zeros of 6x^2+3=7x are x= 7/12+i(sqrt(23))/(12),x= 7/12-i(sqrt(23))/(12)