What are the solutions to the equation 3x^2+4x-32=0 ?

The solutions to the equation 3x^2+4x-32=0 are x= 8/3 ,x=-4

Find the zeros of 3x^2+4x-32=0

The zeros of 3x^2+4x-32=0 are x= 8/3 ,x=-4

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3 x^{2} + 4 x - 32 = 0

x = \frac{8}{3}, x = - 4

Solution steps

3 x^{2} + 4 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 32 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 32) = 20

x_{1, 2} = \frac{- 4 \pm 20}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 20}{2 \cdot 3}, x_{2} = \frac{- 4 - 20}{2 \cdot 3}

x = \frac{- 4 + 20}{2 \cdot 3} : \frac{8}{3}

x = \frac{- 4 - 20}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - 4

x, 7 x^{2} + 8 x - 9 = 10

x^{2} - 7 = - 3 x^{2}

6 y^{2} - y + 2 = 0

3 x^{2} + 10 x - 88 = 0

(x - 6)^{2} - 64 = 0

What are the solutions to the equation 3x^2+4x-32=0 ?
The solutions to the equation 3x^2+4x-32=0 are x= 8/3 ,x=-4
Find the zeros of 3x^2+4x-32=0
The zeros of 3x^2+4x-32=0 are x= 8/3 ,x=-4