What are the solutions to the equation x^2-7=-3x^2 ?

The solutions to the equation x^2-7=-3x^2 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

Find the zeros of x^2-7=-3x^2

The zeros of x^2-7=-3x^2 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

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x^{2} - 7 = - 3 x^{2}

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 1.32287 \dots, x = - 1.32287 \dots

Solution steps

x^{2} - 7 = - 3 x^{2}

Move

7

to the right side

x^{2} = - 3 x^{2} + 7

Move

3 x^{2}

to the left side

4 x^{2} = 7

Divide both sides by

4

x^{2} = \frac{7}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{4}, x = - \frac{7}{4}

\frac{7}{4} = \frac{7}{2}

- \frac{7}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

6 y^{2} - y + 2 = 0

3 x^{2} + 10 x - 88 = 0

(x - 6)^{2} - 64 = 0

12 x^{2} - 4 x + 7 = 0

x^{2} + 8 x + 6 = 0

What are the solutions to the equation x^2-7=-3x^2 ?
The solutions to the equation x^2-7=-3x^2 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2
Find the zeros of x^2-7=-3x^2
The zeros of x^2-7=-3x^2 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2