What are the solutions to the equation 2r^2-11r+5=0 ?

The solutions to the equation 2r^2-11r+5=0 are r=5,r= 1/2

Find the zeros of 2r^2-11r+5=0

The zeros of 2r^2-11r+5=0 are r=5,r= 1/2

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2 r^{2} - 11 r + 5 = 0

r = 5, r = \frac{1}{2}

Decimal Notation

r = 5, r = 0.5

Solution steps

2 r^{2} - 11 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 5 = 9

r_{1, 2} = \frac{- ( - 11 ) \pm 9}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- ( - 11 ) + 9}{2 \cdot 2}, r_{2} = \frac{- ( - 11 ) - 9}{2 \cdot 2}

r = \frac{- ( - 11 ) + 9}{2 \cdot 2} : 5

r = \frac{- ( - 11 ) - 9}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

r = 5, r = \frac{1}{2}

x^{2} - 10 + 9 = 0

a = a^{2} + 4

- 3 (4 x - 16) (20 + 10 x) = 0

- 10 + 2 n^{2} = - 2

2 x = 6 x^{2} - 7

What are the solutions to the equation 2r^2-11r+5=0 ?
The solutions to the equation 2r^2-11r+5=0 are r=5,r= 1/2
Find the zeros of 2r^2-11r+5=0
The zeros of 2r^2-11r+5=0 are r=5,r= 1/2