What are the solutions to the equation -10+2n^2=-2 ?

The solutions to the equation -10+2n^2=-2 are n=2,n=-2

Find the zeros of -10+2n^2=-2

The zeros of -10+2n^2=-2 are n=2,n=-2

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- 10 + 2 n^{2} = - 2

n = 2, n = - 2

Solution steps

- 10 + 2 n^{2} = - 2

Move

10

to the right side

2 n^{2} = 8

Divide both sides by

2

n^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 4, n = - 4

4 = 2

- 4 = - 2

n = 2, n = - 2

2 x = 6 x^{2} - 7

b^{2} = \frac{3}{4}

(4 x - 3) (5 x - 7) = 0

x, - 3 = 4 x^{2} - x - 3

- 5 n^{2} + 2 n - 7 = 0

What are the solutions to the equation -10+2n^2=-2 ?
The solutions to the equation -10+2n^2=-2 are n=2,n=-2
Find the zeros of -10+2n^2=-2
The zeros of -10+2n^2=-2 are n=2,n=-2