What are the solutions to the equation -3(4x-16)(20+10x)=0 ?

The solutions to the equation -3(4x-16)(20+10x)=0 are x=4,x=-2

Find the zeros of -3(4x-16)(20+10x)=0

The zeros of -3(4x-16)(20+10x)=0 are x=4,x=-2

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- 3 (4 x - 16) (20 + 10 x) = 0

x = 4, x = - 2

Solution steps

- 3 (4 x - 16) (20 + 10 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 16 = 0 or 20 + 10 x = 0

Solve

4 x - 16 = 0 : x = 4

Solve

20 + 10 x = 0 : x = - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

- 10 + 2 n^{2} = - 2

2 x = 6 x^{2} - 7

b^{2} = \frac{3}{4}

(4 x - 3) (5 x - 7) = 0

x, - 3 = 4 x^{2} - x - 3

What are the solutions to the equation -3(4x-16)(20+10x)=0 ?
The solutions to the equation -3(4x-16)(20+10x)=0 are x=4,x=-2
Find the zeros of -3(4x-16)(20+10x)=0
The zeros of -3(4x-16)(20+10x)=0 are x=4,x=-2