What are the solutions to the equation y^2+75=-28y ?

The solutions to the equation y^2+75=-28y are y=-3,y=-25

Find the zeros of y^2+75=-28y

The zeros of y^2+75=-28y are y=-3,y=-25

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y^{2} + 75 = - 28 y

y = - 3, y = - 25

Solution steps

y^{2} + 75 = - 28 y

Move

28 y

to the left side

y^{2} + 75 + 28 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} + 28 y + 75 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 1 \cdot 75}{2 \cdot 1}

2 8^{2} - 4 \cdot 1 \cdot 75 = 22

y_{1, 2} = \frac{- 28 \pm 22}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 28 + 22}{2 \cdot 1}, y_{2} = \frac{- 28 - 22}{2 \cdot 1}

y = \frac{- 28 + 22}{2 \cdot 1} : - 3

y = \frac{- 28 - 22}{2 \cdot 1} : - 25

The solutions to the quadratic equation are:

y = - 3, y = - 25

x, f (x + h) = 3 - 5 x - 2 x^{2}

10 x^{2} + 11 x - 90 = 0

x, f (x + 2) = 3 x^{2} + 4 x - 2

x^{2} - 6 x - 39 = 0

199 = 0.1 w^{2} + 2.155 w + 19.985

What are the solutions to the equation y^2+75=-28y ?
The solutions to the equation y^2+75=-28y are y=-3,y=-25
Find the zeros of y^2+75=-28y
The zeros of y^2+75=-28y are y=-3,y=-25