What are the solutions to the equation x^2-6x-39=0 ?

The solutions to the equation x^2-6x-39=0 are x=3+4sqrt(3),x=3-4sqrt(3)

Find the zeros of x^2-6x-39=0

The zeros of x^2-6x-39=0 are x=3+4sqrt(3),x=3-4sqrt(3)

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x^{2} - 6 x - 39 = 0

x = 3 + 43, x = 3 - 43

Decimal Notation

x = 9.92820 \dots, x = - 3.92820 \dots

Solution steps

x^{2} - 6 x - 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 39 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 39) = 83

x_{1, 2} = \frac{- ( - 6 ) \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 8 3}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 8 3}{2 \cdot 1}

x = \frac{- ( - 6 ) + 8 3}{2 \cdot 1} : 3 + 43

x = \frac{- ( - 6 ) - 8 3}{2 \cdot 1} : 3 - 43

The solutions to the quadratic equation are:

x = 3 + 43, x = 3 - 43

199 = 0.1 w^{2} + 2.155 w + 19.985

49 x^{2} - 3 = 13

2 x \cdot (x - 3) - x \cdot (x - 3) = 0

x^{2} - 2 x + 1 - x = - 2 x^{2} + x

5 (x - 2)^{2} = - 20

What are the solutions to the equation x^2-6x-39=0 ?
The solutions to the equation x^2-6x-39=0 are x=3+4sqrt(3),x=3-4sqrt(3)
Find the zeros of x^2-6x-39=0
The zeros of x^2-6x-39=0 are x=3+4sqrt(3),x=3-4sqrt(3)