What are the solutions to the equation 10x^2+11x-90=0 ?

The solutions to the equation 10x^2+11x-90=0 are x= 5/2 ,x=-18/5

Find the zeros of 10x^2+11x-90=0

The zeros of 10x^2+11x-90=0 are x= 5/2 ,x=-18/5

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10 x^{2} + 11 x - 90 = 0

x = \frac{5}{2}, x = - \frac{18}{5}

Decimal Notation

x = 2.5, x = - 3.6

Solution steps

10 x^{2} + 11 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 10 ( - 90 )}{2 \cdot 10}

1 1^{2} - 4 \cdot 10 (- 90) = 61

x_{1, 2} = \frac{- 11 \pm 61}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 11 + 61}{2 \cdot 10}, x_{2} = \frac{- 11 - 61}{2 \cdot 10}

x = \frac{- 11 + 61}{2 \cdot 10} : \frac{5}{2}

x = \frac{- 11 - 61}{2 \cdot 10} : - \frac{18}{5}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{18}{5}

x, f (x + 2) = 3 x^{2} + 4 x - 2

x^{2} - 6 x - 39 = 0

199 = 0.1 w^{2} + 2.155 w + 19.985

49 x^{2} - 3 = 13

2 x \cdot (x - 3) - x \cdot (x - 3) = 0

What are the solutions to the equation 10x^2+11x-90=0 ?
The solutions to the equation 10x^2+11x-90=0 are x= 5/2 ,x=-18/5
Find the zeros of 10x^2+11x-90=0
The zeros of 10x^2+11x-90=0 are x= 5/2 ,x=-18/5