What are the solutions to the equation -x^2+7x+3=0 ?

The solutions to the equation -x^2+7x+3=0 are x=-(-7+sqrt(61))/2 ,x=(7+sqrt(61))/2

Find the zeros of -x^2+7x+3=0

The zeros of -x^2+7x+3=0 are x=-(-7+sqrt(61))/2 ,x=(7+sqrt(61))/2

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- x^{2} + 7 x + 3 = 0

x = - \frac{- 7 + 61}{2}, x = \frac{7 + 61}{2}

Solution steps

- x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

7^{2} - 4 (- 1) \cdot 3 = 61

x_{1, 2} = \frac{- 7 \pm 61}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 61}{2 ( - 1 )}, x_{2} = \frac{- 7 - 61}{2 ( - 1 )}

x = \frac{- 7 + 61}{2 ( - 1 )} : - \frac{- 7 + 61}{2}

x = \frac{- 7 - 61}{2 ( - 1 )} : \frac{7 + 61}{2}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 61}{2}, x = \frac{7 + 61}{2}

x (2 x + 3) - 5 = 6 x

x^{2} + 20 x - 2400 = 0

3 (- 3)^{2} + 2 y^{2} = 36

- 2 x^{2} + 8 x + 2 = 0

p^{2} - 9 = 8 \cdot 5

What are the solutions to the equation -x^2+7x+3=0 ?
The solutions to the equation -x^2+7x+3=0 are x=-(-7+sqrt(61))/2 ,x=(7+sqrt(61))/2
Find the zeros of -x^2+7x+3=0
The zeros of -x^2+7x+3=0 are x=-(-7+sqrt(61))/2 ,x=(7+sqrt(61))/2