What are the solutions to the equation -2x^2+8x+2=0 ?

The solutions to the equation -2x^2+8x+2=0 are x=2-sqrt(5),x=2+sqrt(5)

Find the zeros of -2x^2+8x+2=0

The zeros of -2x^2+8x+2=0 are x=2-sqrt(5),x=2+sqrt(5)

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- 2 x^{2} + 8 x + 2 = 0

x = 2 - 5, x = 2 + 5

Decimal Notation

x = - 0.23606 \dots, x = 4.23606 \dots

Solution steps

- 2 x^{2} + 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 2}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 2 = 45

x_{1, 2} = \frac{- 8 \pm 4 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 5}{2 ( - 2 )}, x_{2} = \frac{- 8 - 4 5}{2 ( - 2 )}

x = \frac{- 8 + 4 5}{2 ( - 2 )} : 2 - 5

x = \frac{- 8 - 4 5}{2 ( - 2 )} : 2 + 5

The solutions to the quadratic equation are:

x = 2 - 5, x = 2 + 5

p^{2} - 9 = 8 \cdot 5

x^{2} - x - 20 = 0

x^{2} - 25 x + 156 = 0

6 (x - 1) = x^{2} + x

2 = x^{2} - 3 x - 8

What are the solutions to the equation -2x^2+8x+2=0 ?
The solutions to the equation -2x^2+8x+2=0 are x=2-sqrt(5),x=2+sqrt(5)
Find the zeros of -2x^2+8x+2=0
The zeros of -2x^2+8x+2=0 are x=2-sqrt(5),x=2+sqrt(5)