What are the solutions to the equation x(2x+3)-5=6x ?

The solutions to the equation x(2x+3)-5=6x are x= 5/2 ,x=-1

Find the zeros of x(2x+3)-5=6x

The zeros of x(2x+3)-5=6x are x= 5/2 ,x=-1

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x (2 x + 3) - 5 = 6 x

x = \frac{5}{2}, x = - 1

Decimal Notation

x = 2.5, x = - 1

Solution steps

x (2 x + 3) - 5 = 6 x

Expand

x (2 x + 3) - 5 : 2 x^{2} + 3 x - 5

2 x^{2} + 3 x - 5 = 6 x

Move

6 x

to the left side

2 x^{2} - 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 5) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 2}

x = \frac{- ( - 3 ) + 7}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 3 ) - 7}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 1

x^{2} + 20 x - 2400 = 0

3 (- 3)^{2} + 2 y^{2} = 36

- 2 x^{2} + 8 x + 2 = 0

p^{2} - 9 = 8 \cdot 5

x^{2} - x - 20 = 0

What are the solutions to the equation x(2x+3)-5=6x ?
The solutions to the equation x(2x+3)-5=6x are x= 5/2 ,x=-1
Find the zeros of x(2x+3)-5=6x
The zeros of x(2x+3)-5=6x are x= 5/2 ,x=-1